Match analytics

Henrique Rocha vs Elmer Moller · Match odds & ELO prediction

Braga • Clay • Oct 1, 2025 • 12:05 PM

Clay

Final score

1 - 2

Winner Elmer Moller

Key insights

Player performance profile

Henrique Rocha

HARDSmall sample

0% · 01 on hard

Games won (last 10)

52%

10 matches tracked

Player Skillset

Based on ~2,836 points across 18 matches

Serve strengthServe strength (Player serve win % - tour average serve win %) scaled by sample size
Shaky
0.647% Pctl
Return strengthReturn strength (Player return win % - tour average return win %) scaled by sample size
Solid
-1.461% Pctl
Pressure IndexPressure Index (Break point performance - baseline point performance) with a small adjustment for tiebreak results
Vulnerable
-3.820% Pctl
Tiebreak win %
Vulnerable
40%24% Pctl

Percentiles compare against tour-level players in TennisTrove.

Elmer Moller

HARDSmall sample

0% · 01 on hard

Games won (last 10)

53%

10 matches tracked

Player Skillset

Based on ~2,502 points across 15 matches

Serve strengthServe strength (Player serve win % - tour average serve win %) scaled by sample size
Vulnerable
-5.21% Pctl
Return strengthReturn strength (Player return win % - tour average return win %) scaled by sample size
Elite
2.197% Pctl
Pressure IndexPressure Index (Break point performance - baseline point performance) with a small adjustment for tiebreak results
Shaky
-2.826% Pctl
Tiebreak win %
Insufficient data

Percentiles compare against tour-level players in TennisTrove.

Match Overview

Henrique Rocha and Elmer Moller are set to meet at the Braga on October 1, 2025 in a clay-court singles match. Rocha enters with a 15–17 record on clay courts in 2025, while Moller has posted a 30–16 mark on clay courts this season. Elo ratings point to a clear statistical advantage for Moller entering this matchup. In their head-to-head history, Moller leads 2–0 over Rocha, including a win in their most recent meeting.

Recent singles form slightly favors Moller, who has won 4 of his last five matches, while Rocha has gone 1–4 over the same span.