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Match analytics

Emma Raducanu vs Iga Swiatek · Match odds & ELO prediction

WTA Australian Open • Hard • Jan 18, 2025 • 12:45 AM

Hard

Final score

0 - 2

Winner Iga Swiatek

Key insights

Player performance profile

Emma Raducanu

HARDSmall sample

0% · 01 on hard

Games won (last 10)

48%

10 matches tracked

Player Skillset

Based on ~8,070 points across 57 matches

Serve strengthServe strength (Player serve win % - tour average serve win %) scaled by sample size
Solid
1.066% Pctl
Return strengthReturn strength (Player return win % - tour average return win %) scaled by sample size
Strong
0.877% Pctl
Pressure IndexPressure Index (Break point performance - baseline point performance) with a small adjustment for tiebreak results
Strong
+4.884% Pctl
Tiebreak win %
Solid
57%66% Pctl

Percentiles compare against tour-level players in TennisTrove.

Iga Swiatek

HARD

60% · 32 on hard

Games won (last 10)

67%

10 matches tracked

Player Skillset

Based on ~12,001 points across 95 matches

Serve strengthServe strength (Player serve win % - tour average serve win %) scaled by sample size
Elite
4.698% Pctl
Return strengthReturn strength (Player return win % - tour average return win %) scaled by sample size
Elite
3.798% Pctl
Pressure IndexPressure Index (Break point performance - baseline point performance) with a small adjustment for tiebreak results
Solid
+1.259% Pctl
Tiebreak win %
Solid
60%71% Pctl

Percentiles compare against tour-level players in TennisTrove.

Match Overview

Emma Raducanu and Iga Swiatek are set to meet at the WTA Australian Open on January 18, 2025 in a hard-court singles match. Raducanu enters with a 17–15 record on hard courts in 2025, while Swiatek has posted a 41–12 mark on hard courts this season. Elo ratings point to a clear statistical advantage for Swiatek entering this matchup. In their head-to-head history, Swiatek leads 5–0 over Raducanu, including a win in their most recent meeting.

Recent singles form slightly favors Swiatek, who has won 4 of his last five matches, while Raducanu has gone 1–4 over the same span.
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