BUILD_STAMP:fix1-no-premium-endpoint-2026-03-05
Match analytics

Branko Djuric vs C. Ye · Match odds & ELO prediction

M25 Monastir 7 • Hard • Oct 8, 2025 • 11:25 AM

Hard

Final score

2 - 1

Winner Branko Djuric

Key insights

Player performance profile

Branko Djuric

HARD

58% · 118 on hard

CLAY

72% · 3915 on clay

Games won (last 10)

53%

10 matches tracked

Player Skillset

Based on ~0 points across 0 matches

Serve strengthServe strength (Player serve win % - tour average serve win %) scaled by sample size
Shaky
0.038% Pctl
Return strengthReturn strength (Player return win % - tour average return win %) scaled by sample size
Strong
0.083% Pctl
Pressure IndexPressure Index (Break point performance - baseline point performance) with a small adjustment for tiebreak results
Shaky
0.048% Pctl
Tiebreak win %
Insufficient data

Percentiles compare against tour-level players in TennisTrove.

C. Ye

Games won (last 10)

42%

8 matches tracked

Player Skillset

Based on ~0 points across 0 matches

Serve strengthServe strength (Player serve win % - tour average serve win %) scaled by sample size
Elite
0.0100% Pctl
Return strengthReturn strength (Player return win % - tour average return win %) scaled by sample size
Vulnerable
0.08% Pctl
Pressure IndexPressure Index (Break point performance - baseline point performance) with a small adjustment for tiebreak results
Elite
0.093% Pctl
Tiebreak win %
Insufficient data

Percentiles compare against tour-level players in TennisTrove.

Match Overview

Branko Djuric and C. Ye are set to meet at the M25 Monastir 7 on October 8, 2025 in a hard-court singles match. Djuric enters with a 11–8 record on hard courts in 2025, while Ye has limited recorded results on hard courts this season. Elo ratings point to a clear statistical advantage for Djuric entering this matchup. In their head-to-head history, Djuric leads 1–0 over Ye, including a win in their most recent meeting.

Recent singles form slightly favors Djuric, who has won 4 of his last five matches, while Ye has gone 1–4 over the same span.
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