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Match analytics

Ekaterina Alexandrova vs Ann Li · Match odds & ELO prediction

Wuhan • Hard • Oct 8, 2025 • 3:10 AM

Hard

Final score

2 - 0

Winner Ekaterina Alexandrova

Key insights

Player performance profile

Ekaterina Alexandrova

HARDSmall sample

50% · 11 on hard

Games won (last 10)

43%

10 matches tracked

Player Skillset

Based on ~11,450 points across 81 matches

Serve strengthServe strength (Player serve win % - tour average serve win %) scaled by sample size
Elite
3.391% Pctl
Return strengthReturn strength (Player return win % - tour average return win %) scaled by sample size
Solid
0.472% Pctl
Pressure IndexPressure Index (Break point performance - baseline point performance) with a small adjustment for tiebreak results
Vulnerable
-6.39% Pctl
Tiebreak win %
Vulnerable
33%17% Pctl

Percentiles compare against tour-level players in TennisTrove.

Ann Li

HARD

38% · 58 on hard

CLAY

63% · 53 on clay

Games won (last 10)

52%

10 matches tracked

Player Skillset

Based on ~10,173 points across 67 matches

Serve strengthServe strength (Player serve win % - tour average serve win %) scaled by sample size
Solid
1.167% Pctl
Return strengthReturn strength (Player return win % - tour average return win %) scaled by sample size
Shaky
-1.239% Pctl
Pressure IndexPressure Index (Break point performance - baseline point performance) with a small adjustment for tiebreak results
Vulnerable
-3.320% Pctl
Tiebreak win %
Shaky
44%32% Pctl

Percentiles compare against tour-level players in TennisTrove.

Match Overview

Ekaterina Alexandrova and Ann Li are set to meet at the Wuhan on October 8, 2025 in a hard-court singles match. Alexandrova enters with a 26–17 record on hard courts in 2025, while Li has posted a 24–16 mark on hard courts this season. Elo ratings suggest a modest statistical edge for Alexandrova, but the gap is not overwhelming. In their head-to-head history, Alexandrova leads 2–1 over Li.

Recent singles form slightly favors Li, who has won 4 of his last five matches, while Alexandrova has gone 1–4 over the same span.
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