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Match analytics

Anna Kalinskaya vs Iga Swiatek · Match odds & ELO prediction

US Open • Hard • Aug 30, 2025 • 11:15 PM

Hard

Final score

0 - 2

Winner Iga Swiatek

Key insights

Player performance profile

Anna Kalinskaya

HARDSmall sample

50% · 11 on hard

Games won (last 10)

46%

10 matches tracked

Player Skillset

Based on ~7,734 points across 55 matches

Serve strengthServe strength (Player serve win % - tour average serve win %) scaled by sample size
Strong
2.181% Pctl
Return strengthReturn strength (Player return win % - tour average return win %) scaled by sample size
Shaky
-1.730% Pctl
Pressure IndexPressure Index (Break point performance - baseline point performance) with a small adjustment for tiebreak results
Shaky
-1.830% Pctl
Tiebreak win %
Shaky
42%30% Pctl

Percentiles compare against tour-level players in TennisTrove.

Iga Swiatek

HARD

60% · 32 on hard

Games won (last 10)

59%

10 matches tracked

Player Skillset

Based on ~11,028 points across 88 matches

Serve strengthServe strength (Player serve win % - tour average serve win %) scaled by sample size
Elite
4.897% Pctl
Return strengthReturn strength (Player return win % - tour average return win %) scaled by sample size
Elite
3.397% Pctl
Pressure IndexPressure Index (Break point performance - baseline point performance) with a small adjustment for tiebreak results
Solid
+2.569% Pctl
Tiebreak win %
Strong
63%78% Pctl

Percentiles compare against tour-level players in TennisTrove.

Match Overview

Anna Kalinskaya and Iga Swiatek are set to meet at the US Open on August 30, 2025 in a hard-court singles match. Kalinskaya enters with a 19–15 record on hard courts in 2025, while Swiatek has posted a 41–12 mark on hard courts this season. Elo ratings point to a clear statistical advantage for Swiatek entering this matchup. In their head-to-head history, Swiatek leads 3–1 over Kalinskaya, including a win in their most recent meeting.

Recent singles form slightly favors Swiatek, who has won 4 of his last five matches, while Kalinskaya has gone 2–3 over the same span.
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