Match analytics

Ashlyn Krueger vs Jessica Pegula · Match odds & ELO prediction

Rome • Clay • May 8, 2025 • 3:10 PM

Clay

Final score

0 - 2

Winner Jessica Pegula

Key insights

Player performance profile

Ashlyn Krueger

HARDSmall sample

0% · 02 on hard

Games won (last 10)

44%

10 matches tracked

Player Skillset

Based on ~7,796 points across 52 matches

Serve strengthServe strength (Player serve win % - tour average serve win %) scaled by sample size
Shaky
0.146% Pctl
Return strengthReturn strength (Player return win % - tour average return win %) scaled by sample size
Vulnerable
-2.913% Pctl
Pressure IndexPressure Index (Break point performance - baseline point performance) with a small adjustment for tiebreak results
Strong
+6.589% Pctl
Tiebreak win %
Strong
69%86% Pctl

Percentiles compare against tour-level players in TennisTrove.

Jessica Pegula

HARDSmall sample

75% · 31 on hard

Games won (last 10)

54%

10 matches tracked

Player Skillset

Based on ~11,097 points across 75 matches

Serve strengthServe strength (Player serve win % - tour average serve win %) scaled by sample size
Elite
3.893% Pctl
Return strengthReturn strength (Player return win % - tour average return win %) scaled by sample size
Solid
0.570% Pctl
Pressure IndexPressure Index (Break point performance - baseline point performance) with a small adjustment for tiebreak results
Solid
+1.259% Pctl
Tiebreak win %
Solid
59%71% Pctl

Percentiles compare against tour-level players in TennisTrove.

Match Overview

Ashlyn Krueger and Jessica Pegula are set to meet at the Rome on May 8, 2025 in a clay-court singles match. Krueger enters with a 4–5 record on clay courts in 2025, while Pegula has posted a 11–5 mark on clay courts this season. Elo ratings point to a clear statistical advantage for Pegula entering this matchup. In their head-to-head history, Pegula leads 4–0 over Krueger, including a win in their most recent meeting.

Recent singles form slightly favors Pegula, who has won 4 of his last five matches, while Krueger has gone 1–4 over the same span.