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Match analytics

Sinja Kraus vs Dominika Salkova · Match odds & ELO prediction

Oeiras • Clay • Apr 15, 2025 • 5:30 PM

Clay

Final score

2 - 0

Winner Sinja Kraus

Key insights

Player performance profile

Sinja Kraus

HARDSmall sample

75% · 31 on hard

Games won (last 10)

48%

10 matches tracked

Player Skillset

Based on ~1,784 points across 13 matches

Serve strengthServe strength (Player serve win % - tour average serve win %) scaled by sample size
Shaky
-1.128% Pctl
Return strengthReturn strength (Player return win % - tour average return win %) scaled by sample size
Solid
-0.061% Pctl
Pressure IndexPressure Index (Break point performance - baseline point performance) with a small adjustment for tiebreak results
Solid
+0.553% Pctl
Tiebreak win %
Strong
60%76% Pctl

Percentiles compare against tour-level players in TennisTrove.

Dominika Salkova

HARDSmall sample

0% · 01 on hard

Games won (last 10)

53%

10 matches tracked

Player Skillset

Based on ~2,882 points across 18 matches

Serve strengthServe strength (Player serve win % - tour average serve win %) scaled by sample size
Shaky
-0.243% Pctl
Return strengthReturn strength (Player return win % - tour average return win %) scaled by sample size
Shaky
-1.730% Pctl
Pressure IndexPressure Index (Break point performance - baseline point performance) with a small adjustment for tiebreak results
Shaky
-1.831% Pctl
Tiebreak win %
Shaky
44%34% Pctl

Percentiles compare against tour-level players in TennisTrove.

Match Overview

Sinja Kraus and Dominika Salkova are set to meet at the Oeiras on April 15, 2025 in a clay-court singles match. Kraus enters with a 41–17 record on clay courts in 2025, while Salkova has posted a 16–12 mark on clay courts this season. Elo ratings suggest a modest statistical edge for Kraus, but the gap is not overwhelming. In their head-to-head history, Salkova leads 4–2 over Kraus, including a win in their most recent meeting.

Recent singles form slightly favors Salkova, who has won 4 of his last five matches, while Kraus has gone 2–3 over the same span.
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