Match analytics

Max Houkes vs Gijs Brouwer · Match odds & ELO prediction

Rotterdam • Hard • Feb 1, 2025 • 12:55 PM

Hard

Final score

0 - 2

Winner Gijs Brouwer

Key insights

Player performance profile

Max Houkes

HARDSmall sample

0% · 01 on hard

Games won (last 10)

59%

10 matches tracked

Player Skillset

Based on ~112 points across 1 matches

Serve strengthServe strength (Player serve win % - tour average serve win %) scaled by sample size
Vulnerable
-1.913% Pctl
Return strengthReturn strength (Player return win % - tour average return win %) scaled by sample size
Solid
-0.773% Pctl
Pressure IndexPressure Index (Break point performance - baseline point performance) with a small adjustment for tiebreak results
Solid
+3.073% Pctl
Tiebreak win %
Insufficient data

Percentiles compare against tour-level players in TennisTrove.

Gijs Brouwer

HARDSmall sample

50% · 11 on hard

Games won (last 10)

44%

9 matches tracked

Player Skillset

Based on ~404 points across 4 matches

Serve strengthServe strength (Player serve win % - tour average serve win %) scaled by sample size
Vulnerable
-3.45% Pctl
Return strengthReturn strength (Player return win % - tour average return win %) scaled by sample size
Shaky
-2.830% Pctl
Pressure IndexPressure Index (Break point performance - baseline point performance) with a small adjustment for tiebreak results
Shaky
-0.445% Pctl
Tiebreak win %
Insufficient data

Percentiles compare against tour-level players in TennisTrove.

Match Overview

Max Houkes and Gijs Brouwer are set to meet at the Rotterdam on February 1, 2025 in a hard-court singles match. Houkes enters with a 9–5 record on hard courts in 2025, while Brouwer has posted a 2–4 mark on hard courts this season. Elo ratings point to a clear statistical advantage for Houkes entering this matchup. In their head-to-head history, Brouwer leads 1–0 over Houkes, including a win in their most recent meeting.

Recent singles form slightly favors Houkes, who has won 5 of his last five matches, while Brouwer has gone 1–4 over the same span.